目标关键代码int getScore(string s) { int score 0; for (int i 0; i s.size(); i) { char currentLetter s[i]; if (isdigit(currentLetter)) score scoreOfNumber; else if (isalpha(currentLetter)) { int ascii currentLetter; if (ascii 0x5A) // Upper-case score scoreOfUCaseLetter; else score scoreOfLetter; } else score scoreOfSpecialChar; } return score; }效果This password is safe. Score: 122 of 100参考GitHub - GordonZhang2024/Password-security-checker: A simple-but-useful password security checker written in C创作不易小小的支持一下吧